Tom Nicholson
29-Apr-2004 12:13
If you want to convert an integer into an English word string, eg. 29 ->
twenty-nine, then here's a function to do it.
Note on use of
fmod()
I used the floating point fmod() in preference to the %
operator, because % converts the operands to int, corrupting values outside
of the range [-2147483648, 2147483647]
I haven't bothered with
"billion" because the word means 10e9 or 10e12 depending who you
ask.
The function returns '#' if the argument does not represent a
whole number.
<?php
$nwords = array( "zero",
"one", "two", "three", "four",
"five", "six", "seven",
"eight", "nine", "ten", "eleven",
"twelve", "thirteen",
"fourteen", "fifteen", "sixteen",
"seventeen", "eighteen",
"nineteen", "twenty", 30 => "thirty", 40
=> "forty",
50 => "fifty",
60 => "sixty", 70 => "seventy", 80 =>
"eighty",
90 => "ninety"
);
function int_to_words($x) {
global $nwords;
if(!is_numeric($x))
$w = '#';
else if(fmod($x, 1) != 0)
$w = '#';
else {
if($x < 0) {
$w = 'minus
';
$x = -$x;
} else
$w = '';
//
... now $x is a non-negative integer.
if($x < 21) // 0 to
20
$w .= $nwords[$x];
else if($x < 100) { // 21
to 99
$w .= $nwords[10 * floor($x/10)];
$r =
fmod($x, 10);
if($r > 0)
$w .= '-'.
$nwords[$r];
} else if($x < 1000) { // 100 to 999
$w .= $nwords[floor($x/100)] .' hundred';
$r = fmod($x,
100);
if($r > 0)
$w .= ' and '.
int_to_words($r);
} else if($x < 1000000) { // 1000 to
999999
$w .= int_to_words(floor($x/1000)) .' thousand';
$r = fmod($x, 1000);
if($r > 0) {
$w .= '
';
if($r < 100)
$w .= 'and ';
$w .= int_to_words($r);
}
} else { //
millions
$w .= int_to_words(floor($x/1000000)) .' million';
$r = fmod($x, 1000000);
if($r > 0) {
$w .= ' ';
if($r < 100)
$word .= 'and
';
$w .= int_to_words($r);
}
}
}
return $w;
}
?>
settype
