Description
int
stripos ( string haystack, string needle [, int offset])
Returns the numeric position of the first occurrence of
needle in the haystack
string. Unlike strpos(),
stripos() is case-insensitive.
Note that the needle may be a string of one or
more characters.
If needle is not found,
stripos() will return boolean FALSE.
| 警告 |
这个函数可能返回 Boolean FALSE,也可能返回一个与 FALSE 相等地非 Boolean 值,比如 0 或者 "" 。请参阅 Booleans 的有关章节以获取更多信息。请使用 === 操作符 来测试该函数的返回值。 |
例子 1. stripos() examples |
<?php
$findme = 'a';
$mystring1 = 'xyz';
$mystring2 = 'ABC';
$pos1 = stripos($mystring1, $findme);
$pos2 = stripos($mystring2, $findme);
// Nope, 'a' is certainly not in 'xyz'
if ($pos1 === false) {
echo "The string '$findme' was not found in the string '$mystring1'";
}
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' is the 0th (first) character.
if ($pos2 !== false) {
echo "We found '$findme' in '$mystring2' at position $pos2";
}
?>
|
|
If needle is not a string, it is converted
to an integer and applied as the ordinal value of a character.
The optional offset parameter allows you
to specify which character in haystack to
start searching. The position returned is still relative to the
the beginning of haystack.
See also strpos(), strrpos(),
strrchr(), substr(),
stristr(), strstr(),
strripos() and str_ireplace().